KITFORMA · EDITORIAL ANSWER
Why does assigning the result of list.sort turn my list into None?
KitForma editorial guide. `list.sort()` changes the existing list and returns `None`. It is an in-place operation, not a sorted-value constructor.
Step-by-step answer
list.sort() changes the existing list and returns None. It is an in-place operation, not a sorted-value constructor.
Use items.sort() without assignment when mutation is intended, or ordered = sorted(items) to obtain a new list. Test that the original order remains unchanged in the second case. For records, pass a key such as key=lambda row: row["created_at"] and define how missing values are handled. Sorting is stable, but that does not make equal keys unique or guarantee the same order when the original input order varies. Add an explicit tie-breaker when reproducible ordering matters.Sources and verification
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